Plate Loaded Machine
Plate Loaded Machine
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Problems with Young's Modulus!?
Having a problem with an assignment - A simple machine comprising 2 pillars, 2 plates and a lead screw is used to press an object.
Part (i) is –
What diameter must the pillars be to sustain a load of 25kN, as applied by the lead screw with a maximum permissible stress of 120MPa?
Length = 500mm
Matl - Carbon Steel Yield Strength - 310MPa
Modulus of Elasticity - 210 x 10^9 N/m^2
For this I am getting 11.52mm DIA. For this i used:
A = F/ Stress
= 12.5 x10^3 / 120
However part two:
What diameter must the pillars be to limit the extension to 2mm?
I worked out the strain (Extension / Original length) = 0.004.
Can anyone give me any pointers as to what I should do next?
Any help would be much appreciated!
Cheers
Calum
Calum,
The answer is at the tip of your pencil. You have got the strain. The Extension is 2mm. It means that Strain * original length =2mm,
Strain now needs to be calculated. Once you get the strain, multiply it by the Youngs Modulus (Modulus of Elasticity), you get the stress. Now, the Force is known (25kN / 2) You can get the area and hence the diameter.
All the Best.
Cheers.


US $345.00












































































