Solid Fusion
Solid Fusion
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 Body Solid Assissted Chin Dip Combo gym w weights stack  US $1,499.00
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 Bayou Fitness Commercial Rated 11 Ga Home Gym E 8640 US $1,598.00
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 Bayou Fitness Commercial Rated 11 Gauge Home Gym E 8640 US $1,712.86
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 Body Solid Fusion 500 Personal Trainer F500 US $1,575.00
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 Body Solid Fusion Vertical Knee Raise Dip Pull Up US $460.00
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 Body Solid FUSION 500 Personal Trainer Home Gym US $1,799.00
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 Body Solid Weight Assisted Dip and Chin Station US $1,375.00
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 Body Solid Fusion 600 Personal Trainer F600 US $2,275.00
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 Body Solid Fusion 500 Personal Trainer F500 US $1,795.00
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 Body Solid Fusion 600 Personal Trainer Home Gym F600 2 210 lb weight stack US $2,275.00
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 Body Solid Fusion 500 Personal Trainer Home Gym F500 2 210 lb weight stack US $1,615.50
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 Body Solid Fusion 400 Personal Trainer Home Gym F400M 1 160 lb weight stack US $1,409.00
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 Body Solid Fusion 400 Personal Trainer F400 US $1,799.00
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 BODY SOLID FUSION 600 GYM AUTHORIZED DEALERS FULL WARRANTY US $2,275.00
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 Powerline Smith Machine PSM144X US $575.00
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 Home gym and Smith Machine from Prospot Fitness SSG US $899.00
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 Body Solid Fusion 400 Personal Trainer F400 US $1,399.00
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 PSM1442XS Powerline Smith Machine Package by Body Solid US $1,250.00
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 home gym US $800.00
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How to solve Heat of Fusion question?
I have no idea how to solve this problem. Suppose that heat was added to a 21.8 gram sample of solid zinc at the rate of 9.84J/s. After the temperature reached the normal melting point of zinc, 420 degrees C, it remained constant for 3.60 minutes. Calculate the change in heat of fusion at 420 degrees C, in J /mol, for zinc.
You're given the rate in J/s, and the time. So J/s * s => J. You now know the total energy placed into the sample during the time the temperature was constant.
You're given the material (zinc) and the mass. You can go find the molecular weight of zinc. Mass (g) divided by molecular weight (g/mol) yields the moles of substance.
Now you can directly calculate heat of fusion (J/mol) by dividing. Keep track of all your units.