V2 Bumper Pair
V2 Bumper Pair
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 45 lb Pendlay V2 Olympic Rubber Bumper Plate 45lb Set  US $109.99
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 10 lb Pendlay V2 Olympic Rubber Bumper Plate 10lb Set US $44.99
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 15 lb Pendlay V2 Olympic Rubber Bumper Plate 15lb Set US $59.99
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 25 lb Pendlay V2 Olympic Rubber Bumper Plate 25lb Set US $69.99
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 35 lb Pendlay V2 Olympic Rubber Bumper Plate 35lb Set US $99.99
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 55 lb Pendlay V2 Olympic Rubber Bumper Plate 55lb Set US $129.99
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pair of bumper cars physics help? HARD physics question??
A pair of bumper cars in an amusement park ride collide in a perfectly elastic collision as one approaches the other directly from the rear. One has a mass of m1 = 450 kg and the other m2 = 550 kg, owing to differences in passenger mass. The lighter one approaches at v1 = 4.50 m/s and the other is moving at v2 = 3.70 m/s.
a)Calculate their velocities after the collision
b) the change in momentum of each
...
i was told to use this, but i'm confused
i know the values for m1, m2, v1, v2, but what is the initial velocity? and how do i solve for momentum.??
V1f= [(m1-m2)/M]x v1i+ [2(m2)/M]x v2i
V2f= [2(m1)/M]x v1i+ [(m2-m1)/M]x v2i
my teacher taught us to use this equation...
m1vi+m2Vi= v(m+m)
soo you do
450(4.50) + 550(3.70)= vf(1000)
2025+2035= Vf(1000)
4060=VF(1000)
4060/ 1000= 4.06
Vf= 4.06 m/s
and for momentum it's
p=mv so i think you do
1000(4.06)=4060